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6v^2+21v-147=0
a = 6; b = 21; c = -147;
Δ = b2-4ac
Δ = 212-4·6·(-147)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-63}{2*6}=\frac{-84}{12} =-7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+63}{2*6}=\frac{42}{12} =3+1/2 $
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